50 Averages Aptitude Questions and Answers for SSC, Bank & Competitive Exams

Q: What is the formula of average?

The formula of average is: Average = Sum of all values ÷ Number of values

Q: How do you solve average problems quickly?

To solve average problems quickly: Use the average formula Multiply average by total numbers to find sum Use shortcuts for consecutive numbers

Q: Are average questions asked in bank exams?

Yes. Average problems are frequently asked in banking exams like SBI, IBPS, and RBI.

Q: What is the average of consecutive numbers?

The average of consecutive numbers is the middle number. Example: Average of 5, 6, 7, 8, 9 = 7

Q: Why is average important in aptitude?

Average helps simplify large sets of numbers into a single value and is commonly tested in competitive exams.

Averages Aptitude Questions and Answers – Concept and Basics

Average aptitude questions are very common in SSC, Bank, Railway, GRE, CAT, and other competitive exams. Understanding the concept of average helps you solve many quantitative aptitude problems quickly.

In simple terms, average represents the central value of a group of numbers. Once you understand the formula and shortcuts, average problems become very easy to solve.

This page provides:

Average formulas
Quick tricks and shortcuts
Solved examples
Average aptitude questions and answers
Practice questions for competitive exams

What is Average in Aptitude?

The average is calculated by dividing the total sum of numbers by the number of values.

Average helps us represent a large set of numbers with a single value.

Formula:

Average = Sum of observations ÷ Number of observations

Example

If the marks of five students are:

60, 70, 80, 90, 100

Average = (60 + 70 + 80 + 90 + 100) / 5
Average = 80

Difference Between Mean and Average

Average is defined as the sum of the values divided by the total number of words.

Mean is defined as the sum of the list’s largest and lowest numbers divided by two.

Averages Formula

Students can use the following important average formulas to answer about averages:

Average of first n natural numbers = (n+1) / 2
Average of squares of first n natural numbers = (n+1) (2n+1) / 6
Average of cubes of first n natural numbers = n (n+1)² / 4
Average of first n even numbers = n + 1
Average of squares of first n even numbers = 2 (n+1) (2n+1) / 3
Average of cube of first n even numbers = 2n (n+1)2
Average of first n odd numbers = n
Average of squares of first n odd numbers = (2n+1) (2n-1) / 3
Average of cube of first n odd numbers = n(2n² – 1)

Average Online Practice Aptitude Test with Answers
Averages Test 1	Averages Test 2	Averages Test 3

Average Short Tricks for Competitive Exams

Using tricks can help you solve problems much faster in exams.

Trick 1: When a New Number is Added

If a new number is added to a group:

New Sum = Old Sum + New Number

Trick 2: When One Number is Replaced

Difference = New Number − Old Number

Adjust the average accordingly.

Trick 3: Consecutive Numbers

The average of consecutive numbers is the middle number.

Example:

Average of 10, 11, 12, 13, 14 = 12

Solved Average Aptitude Questions

Q1. 20 boys go for dinner. 16 of them spent Rs. 64 each on their dinner and the rest spent Rs 4 more than the average expenditure of all 20. What was the total money spent by them?

a) 1200

b) 1500

c) 1800

d) 1300

e) None of these

Solution:

Q2. If the square root of the average ‘A’ of 11 numbers is increased by A, the result is another value B which is the average of first 10 of the 11 numbers used before. Then the 11th number (in terms of A is) is –
a. A + 10√A
b. A – 10√A
c. 10A + √A
d. 10A – √A
e. None of the above

Solution:
Let the sum of first ten numbers be x & let the 11th no. be y
So, A = (x + y) / 11 …(1) Also, B = x / 10 …(2)
ATQ, B = A + √A
or, x/10 = A+ √A {using (2)}
or, x =10(A+ √A) putting in (1)
y = 11A – x = 11A – (10 A+ 10√A) = (A – 10√A)

Average Questions and Answers PDF: Click Here

Q3. In a town a standard tax of Rs. 2000 has to be paid every month on an annual salary up to Rs. 45000 and an additional amount which is 15% of the salary exceeding Rs. 45000 has to be paid. If Ramesh pays an average of Rs. 2750 per month, then what is his average monthly salary?
a. Rs. 8,400
b. Rs. 8,750
c. Rs. 12,000
d. Rs. 9,000
e. Rs. 12,500

Solution:
Standard tax for 12 months = 2000 × 12 = Rs. 24,000
Amount paid by Ramesh = 2750 × 12 = Rs. 33,000
Difference = Rs. 9,000
Let exceeding salary = Rs. x. Then
15x/100 = 9000 ⇒ x =60,000

So, total annual salary of Ramesh = 45,000 + 60,000 = Rs. 1,05,000
Required monthly Salary = Rs. 8750

Q4. Average marks of boys of class is 78 while average marks of girls of the same class is 86. If average marks of all students is M and ratio of number of boys to number of girls in the class is N : 5 then which of the following can be the value of (M – N).
a. 90
b. 96
c. 88
d. 87
e. 80

Solution:
78 < M < 86
0 < N
M – N < 86
Only option possible is option E.

Q5. Average of 11 numbers is 71 and the average of first 5 numbers is 73. If average of last 4 numbers is 84 and the ratio of 6th and 7th number is 9 : 7, then find the 6th number.
a) 27
b) 36
c) 45
d) 54
e) None of these

Solution:
Let the 6th number = 9x, then 7th number = 7x
According to question
11 × 71 = 5 × 73 + 9x + 7x + 4 × 84
⇒ 781 = 365 + 16x + 336
⇒ 16x = 781 – (365 + 336) = 80
⇒ x = = 5
Hence, the 6th number = 9x = 9 × 5 = 45

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Q6. In a class of seven students, one student of weight 140 kgs is replaced by a student of weight 119 kgs, then the average weight of the class is increased or decreased by how much kg?
a) 21
b) 14
c) 7
d) 5
e) 3

Solution:
Required decrease in the average weight of the class = (140-119)/ 7 = 21/7 = 3 kgs.

Q7. The average marks obtained by 80 students in Math is 42. If the average marks of the passed students is 48 while the average marks of the failed students is 32, then find the difference of number of students who passed and failed in the math exam.
a) 30
b) 40
c) 50
d) 60
e) 20

Solution: E
Let passed students and failed students be P and F
42 × 80 = 48 × P + 32 × F ……(i)
and P + F = 80 …….(ii)
Solving (i) and (ii) , we get
P = 50 and F =30
Required difference = 50 – 30 = 20

Q8. There are two sections in a company. Section A has 30 employees and section B has 40 employees. The average salary of employees of section A and employees of section B is Rs. 5000 and Rs. 6000 respectively. Find the average salary of all the employees in the company.
a) Rs. 5571.43
b) Rs. 5000.02
c) Rs. 4872.12
d) Rs. 5000
e) None of these

Solution: A
Required average salary of all the employees in the company =(5000*30 + 6000 * 40)/(30+40)= Rs. 5571.428

Why Average Questions Are Important in Competitive Exams

Average questions are frequently asked in:

SSC Exams
Banking Exams
Railway Exams
GRE Quantitative Tests
CAT Exams

They test your ability to quickly calculate values and understand number relationships.

FAQs on Average Aptitude Questions

What is the formula of average?